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Question

If we have a pure Na2SO4.5H2O sample and it contains 2.2×1010 electrons, the mass of the sample is x×1014 g. x is

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Solution

Number of electrons in 1 molecule of Na2SO4.5H2O=120
120×6.022×1023 electrons are present in 1 mole of Na2SO4.5H2O
2.2×1010 electrons will be present in 2.2×1010120×6.022×1023 moles of Na2SO4.5H2O
=3.04×1016 moles of Na2SO4.5H2O
Mass of Na2SO4.5H2O=no.of moles×molar mass
=3.04×1016×232=7.05×1014 g

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