If we have a pure Na2CO3 sample that contains a total of 7.8286×1024 electrons, then find the number of moles of Na2CO3 present in the sample.
A
0.5 moles
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B
0.3 moles
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C
0.7 moles
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D
0.25 moles
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Solution
The correct option is D 0.25 moles Total number of electrons present in one molecule of Na2CO3=(11×2)+6+(3×8)=52. So, 52×6.022×1024 electrons are present in 1 mole of Na2CO3 Therefore, 7.8286×1024 electrons will be present in =7.8286×102452×6.022×1023 moles of Na2CO3 = 0.25 moles of Na2CO3