Question

If we have a pure $NaN{O}_3$ sample that contains a total of 8.4 kilomoles of electrons, find the number of moles of $NaN{O}_3$ present in the sample.

• A. 200 moles
• B. 2 moles
• C. 0.2 moles
• D. 400 moles

Answer 1

The correct option is A 200 moles

Total number of electrons present in 1 formula unit of $NaN{O}_3=11+7+24=42$

So, the total number of electrons present in one mole of $NaN{O}_3=42\times 6.022\times {10}^{23}$

The moles of $NaN{O}_3$ that would have 8.4 kilomoles of electrons will be
$=\frac{8.4\times 1000\times 6.022\times {10}^{23}}{42\times 6.022\times {10}^{23}}$
$=$ 200 moles