If we multiply first 50 prime numbers, then how many zeros will such a product have at the end?
We need 2's and 5's to get zeros. 2 is the only even prime number. So, the number of zeros is 1.
Let S be the set of prime numbers greater than or equal to 2 and less than 100. Multiply all elements of S. With how many consecutive zeros will the product end?
With how many zeroes does the product of the first 2007 consecutive prime numbers each?