Question

If we plot a graph between ${\log }_{10}k$ and $\frac{1}{T}$ by Arrhenius equation, the slope is:

• A. $-E_a/R$
• B. $+E_a/R$
• C. $-\frac{E_a}{2.303R}$
• D. $+\frac{E_a}{2.303R}$

Answer 1

Answer: (C)

$-\frac{E_a}{2.303R}$

According to the Arrhenius equation:

$k=A{e}^{\frac{-E_a}{RT}}$

Taking log on both sides we get.

$\log k=-\frac{E_a}{2.303RT}+\log A$

Comparing it to : $y=mx+c$

Slope $=\frac{-E_a}{2.303R}$