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If we plot a graph of freuency of radiation against the stopping potential of photoelectron, its slope would be equal to (1) 6.625×10^{-34} (2) 3.656×10^{12} (3) 2.414×10^{14} (4) 6.529×10^{18

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Q. If we plot a graph of stopping potential of photoelectrons against the frequency (in hertz) of radiation that has emitted, then its slope would be:
(

h = 6.6 \times 10^{- 34})

Q. If we plot a graph of stopping potential of photoelectrons against the frequency (hertz) of radiation that has emitted it, then it's slope would be:

Q. The threshold frequency of a certain material is

3 \times 10^{14} Hz .

If it is illuminated by a radiation of frequency

6 \times 10^{14} Hz

, then the stopping potential will be

[Take h = 6.62 \times 10^{- 34} Js]

Q. The maximum kinetic energy (

E_{k}

) of emitted photoelectrons against frequency

ν

of incident radiation is plotted as shown in fig. The slope of the graph is equal to

Q. Match List I(Type of Electromagnetic radiation) with List II(Corresponding Frequency) and select the correct answer using the codes given.

List I	List II
A. Radio waves	$1$ . $10^{16} - 10^{14}$ Hz
B. Ultraviolet waves	$2$ . $10^{10} - 10^{8}$ Hz
C. Visible light	$3$ . $10^{- 6} - 10^{- 3}$ Hz
D. X-rays	$4$ . $10^{14} - 7 \times 10^{12}$ Hz
	$5$ . $10^{18} - 10^{16}$ Hz

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