MyQuestionIcon

1

You visited us 1 times! Enjoying our articles? Unlock Full Access!

Modulus of a Complex Number

If we plot ...

Question

If we plot $| Z_{1} | = 2$ and $| Z_{2} - 6 - 8 i | = 4$ , on the argand plane, the locus of $Z_{1}$ and $Z_{2}$ are

A

two circle touching each other

No worries! We‘ve got your back. Try BYJU‘S free classes today!

B

two circles neither touching nor intersecting

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

C

two circles intersecting

No worries! We‘ve got your back. Try BYJU‘S free classes today!

D

none of these

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is B two circles neither touching nor intersecting
Two circles neither touching nor intersecting.

Suggest Corrections

thumbs-up

0

Similar questions

| Z_{1} - 3 - 4 i | = 2

| Z_{2} - 3 - 4 i | = 5

, then on the argand plane, the locus of

Z_{1}

Z_{2}

| z - z_{1} | = | z_{1} | a n d | z - z_{2} | = | z_{2} |

be the equation of two circles. If the circles touch each other, then

Q. Assertion :The locus of the centre of a circle which touches the circles

| z - z_{1} | = a

| z - z_{2} | = b

z, z_{1}, z_{2}

are complex numbers) will be hyperbola. Reason:

| z - z_{1} | - | z - z_{2} | < | z_{2} - z_{1} |

\Rightarrow z

lies on the hyperbola.

Q. The locus of the centre of the circle which touch the circle

| z - z_{1} | = a

| z - z_{2} | = b

| a - b | < | z_{1} - z_{2} |

z, z_{1}, z_{2}

are complex numbers will be

Q. The locus of the centre of a circle which touches the circle

| z - z_{1} | = a

| z - z_{2} | = b

, externally (where

z_{1}, z_{2}, ϵ C)

View More

Join BYJU'S Learning Program

similar_icon

Related Videos

lock

Geometric Representation and Trigonometric Form

MATHEMATICS

Watch in App

explore_more_icon

Explore more

Modulus of a Complex Number

Standard XII Mathematics

Join BYJU'S Learning Program

CrossIcon