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Froth Floatation

If we start w...

Question

If we start with $100$ kg of ore (containing $7.5 %$ rutile), pure $T i O_{2}$ obtained is :

A

4.8825

kg

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B

7.3238

kg

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C

9.7650

kg

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D

2.4413

kg

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Solution

The correct option is A $4.8825$ kg
According to the balanced reactions, two moles of $T i O_{2}$ (ore) forms two moles of high purity, $T i O_{2}$ .
So, if we start with $100$ kg of ore (containing $7.5 %$ rutile), it produces $7.5 \times 0.7 \times 0.93 = 4.8825$ kg of $T i O_{2}$ .

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