If we substract $- 3 p^{2} q^{2}$ from $p^{2} q^{2}$ , then we get

- 4 p^{2} q^{2}

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- 2 p^{2} q^{2}

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2 p^{2} q^{2}

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4 p^{2} q^{2}

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Solution

The correct option is D $4 p^{2} q^{2}$
$p^{2} q^{2} - (- 3 p^{2} q^{2})$
$= 4 p^{2} q^{2}$

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Similar questions

Add: $2 p^{2} q^{2} - 3 p q + 4$ and $5 + 7 p q - 3 p^{2} q^{2}$

2 p^{2} q^{2} - 3 p q + 4, 5 + 7 p q - 3 p^{2} q^{2}

2 p^{2} q^{2} - 3 p q + 4, 5 + 7 p q - 3 p^{2} q^{2}

2 p^{2} q^{2} - 3 p q + 4 = 0

5 + 7 p q - 3 p^{2} q^{2} = 0

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