If we subtract 2m from both sides of the equation 2+2m=5m-1, we will come up with_____.
The equation of a particle executing SHM is x=(5m)sin[(π s−1)t+π3]. What is its amplitude, time period, maximum speed and velocity. At t = 1s?
The given equation is 2x+4=18
Which number do we subtract on both sides of the equation so that only the variable remains on one side of the equation?