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Question

Question 5

If we subtract 3x2y2 from x2y2, then we get
a) 4x2y2
b) 2x2y2
c) 2x2y2
d) 4x2y2

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Solution

d) 4x2y2
​​​​​​​Given, monomials are 3x2y2 and x2y2. Now, we have to subtract the first one from the second one.
i.e. x2y2(3x2y2)=x2y2(3)x2y2=x2y2+3x2y2=(1+3)x2y2=4x2y2

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