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Question

If we subtract the sum of digits of any two digit number from the number we get a multiple of :


A

3

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B

5

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C

9

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D

7

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Solution

The correct options are
A

3


C

9


Let the Digit in unit's place be m and that at ten's place be n

General form of the number will be 10n + m

Sum of the digits = n + m

Now, when we do the subtraction of the sum of digits from the number we get :

10n + m - n - m = 9n

It is always divisible by 9 and

it will also be divisible by 3


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