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Question

If we treat a solution of Sodium dichromate with KCl, the orange crystals that crystallize out is:

A
Sodium Chloride
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B
Sodium oxide
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C
Sodium chromate
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D
Potassium Dichromate
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Solution

The correct option is D Potassium Dichromate
The reaction that we are looking for is:
Na2Cr2O7+2KClK2Cr2O7+2NaCl
The orange crystals thus obtained is Potassium Dichromate. It is a very important chemical compound that finds extensive use as an oxidant. For instance, it is used to oxidize alcohols in organic chemistry.

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