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Question

If work done by the system is 300 joule when 100 cal, heat is supplied to it. The change in internal energy during the process is :-

A
-200 J
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B
400 J
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C
720 J
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D
120 J
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Solution

The correct option is B 120 J
Solution:- (D) 120J
As the work is done by the system and heat is supplied to the system.
Therefore,
q=100 cal=420J
w=300J

Now from first law of thermodynamics,
ΔU=q+W
ΔU=420+(300)
ΔU=120J

Hence the change in internal energy during the process is 120J.

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