Question

If work done in moving a charge $20mC$ from infinity to a point in an electric field is$15J$, then what is the electric potential at this point?

Answer 1

Step 1: Given data

Charge $Q=20mC$

work done $w=15J$

$v$ is the potential energy=?

Step 2: Definition of electric potential:

The amount of work that is done in order to move a unit charge from a reference point to a specific point inside the field without producing an acceleration.

Step 3: Finding the electric potential

Work done is given by,

$$\begin{gathered} w=Q\times v \\ v=\frac{w}{Q} \\ v=\frac{15}{20\times {10}^{-3}} \\ v=7.5\times {10}^{2}volt \end{gathered}$$

Thus, the electric potential for moving charge is $v=7.5\times {10}^{2}volt$.