If work function of metal is 3 eV then threshold wavelength will beA- 4125 AB- 4000 AC- 4500 AD- 5000 A

The correct option is A 4125 ∘A λ_0 =12375/W_0 (eV)=12375/3=4125 ∘A ...

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If work function of metal is 3eV then threshold wavelength will be

$4125 \circ A$

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$4000 \circ A$

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$4500 \circ A$

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$5000 \circ A$

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