If x<0 is a real number, then arg(x)=
Let z=x,x<0
Clearly, z is purely real number and it lies on negative x
As arg(x)=π ∴arg(z)=π
Hence, if x<0 is a real number, then
arg(x)=π
If x is a real number then |x|=xifx≥0|x|=_______ifx<0