If $x < 0, y < 0$ then $log (x y) =$

log x + log y

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log (- x) + log (- y)

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- log x - log y

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none of these

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Solution

The correct option is B $log (- x) + log (- y)$
Given $x < 0, y < 0 \Rightarrow (- x) > 0, (- y) > 0$
Now,
$log (x y)$
$= log {(- x) (- y)}$
$= log (- x) + log (- y)$ [ Since $log x$ is defined for $x > 0$ ]

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