If x-12=-12, then x= _________
Find the value of x :
Given, x-12=-12
Add 12 on both sides, we get,
⇒x-12+12=-12+12⇒x-0=0⇒x=0
Hence, x=0.
{1(sec2θ−cos2θ)+1(cosec2θ−sin2θ)}(sin2θcos2θ)=1−sin2θcos2θ2+sin2θcos2θ
If f=x1+x2+13(x1+x2)3+15(x1+x2)5+... to ∞ and g=x−23x3+15x5+17x7−29x9+..., then f=d×g. Find 4d.