If(x+1)/(2x+3)=3/8, then x=

1/4

No worries! We‘ve got your back. Try BYJU‘S free classes today!

1/3

No worries! We‘ve got your back. Try BYJU‘S free classes today!

1./6

No worries! We‘ve got your back. Try BYJU‘S free classes today!

1/2

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

Open in App

Solution

The correct option is D 1/2
Given (x+1)/ (2x+3) = 3/8
on rearranging ,
$8 (x + 1) = 3 (2 x + 3)$
$8 x - 6 x = 9 - 8$
$2 x = - 1$
$x = 1 / 2$

Suggest Corrections

Similar questions

(1 + \frac{1}{2}) (1 + \frac{1}{3}) (1 + \frac{1}{4}) (1 + \frac{1}{5}) (1 + \frac{1}{6}) (1 + \frac{1}{7}) (1 + \frac{1}{8})

f (x) = {\begin{matrix} k - 2 x, i f x \leq - 1 2 x + 3, i f x > - 1 \end{matrix}},

f (x) = {\begin{matrix} k - 2 x, i f x \leq 1 2 x + 3, i f x > - 1 \end{matrix}}

1 + \frac{2}{3} (\frac{1}{8}) + \frac{2 \times 5}{3 \times 6} {(\frac{1}{8})}^{2} + \frac{2 \times 5 \times 8}{3 \times 6 \times 9} {(\frac{1}{8})}^{3} + . . . .

f (x) = ⎧ ⎪ ⎪ ⎪ ⎪ ⎪ ⎪ ⎪ ⎪ ⎪ ⎪ ⎪ ⎪ ⎨ ⎪ ⎪ ⎪ ⎪ ⎪ ⎪ ⎪ ⎪ ⎪ ⎪ ⎪ ⎪ ⎩ \begin{matrix} (1 + a x)^{\frac{1}{x}}, if x < 0 b, if x = 0 \frac{(x + c)^{\frac{1}{3}} - 1}{(x + 1)^{\frac{1}{2}} - 1}, if x > 0 \end{matrix}

x = 0

Join BYJU'S Learning Program