If {(x, -1), (2y, 6), (1, -z)} is an identity function, what is the value of x + y + z?
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Solution

The correct option is A 1
{(x, -1), (2y, 6), (1, -z)} is an identity function.

We know that f(x) is an identity function if f(x) = x.

so, x = -1

2y = 6 $⟹$ y = 3

1 = -z $⟹$ z = -1
Hence, x + y + z = -1 + 3 - 1 = 1

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