If $(x - 1)^{3} = 8$ , what is the valie of $(x + 1)^{2}$ ?

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Solution

$(x - 1)^{3} = 8$
$∴ (x - 1) = \sqrt{8}$
$∴ x - 1 = 2$
$∴ x = 2 + 1 = 3$
$∴ (x + 1)^{2} = (3 + 1)^{2}$
$∴ (x + 1)^{2} = 1 +$
$∴$ Value is $16$

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If (x−1)3=8, what is the valie of (x+1)2?

(x−1)3=8∴(x−1)=√8∴x−1=2∴x=2+1=3∴(x+1)2=(3+1)2∴(x+1)2=1+∴ Value is 16

If $(x - 1)^{3} = 8$ , what is the valie of $(x + 1)^{2}$ ?

$(x - 1)^{3} = 8$
$∴ (x - 1) = \sqrt{8}$
$∴ x - 1 = 2$
$∴ x = 2 + 1 = 3$
$∴ (x + 1)^{2} = (3 + 1)^{2}$
$∴ (x + 1)^{2} = 1 +$
$∴$ Value is $16$