If $(x - 1)^{3}$ = 8, what is the value of $(x + 1)^{2}$

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Solution

$(x - 1)^{3}$ = 8

$\Rightarrow$ $(x - 1)^{3} = 2^{3}$

Comparing, we get $x - 1 = 2$

$\Rightarrow$ x = 2 + 1 = 3

Now, $(x + 1)^{2}$ = $(3 + 1)^{2}$ = $(4)^{2} = 16$

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