Question

If $(x-1{)}^4-16=0$, then the sum of nonreal complex values of x is

• A. 2
• B. 0
• C. 4
• D. none of these

Answer 1

The correct option is A 2

$(x-1{)}^4-16=0$
$\Rightarrow (x-1{)}^2=\pm 4=4,4i^2$
$\Rightarrow x-1=\pm 2,\pm 2i$
$\Rightarrow x=-1,3,1-2i,1+2i$
Thus sum of non-real complex values of $x$ is $=1-2i+1+2i=2$