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Question

If x1.41x=1
Then find the value of x.

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Solution

Given that,
x1.41x=1t=xt2=xt21.4t1=0t214t101=010t214t1010=010t214t10=02(5t27t5)=0t=7±(7)24×5×(5)2×5t=7±49+10010x=7±14910x=(7+14910)2x=(7149)1002

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