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Question

If (x+1) and (x1) are factors of mx3+x22x+n, find the value of m and n.

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Solution

Let, f(x)=mx3+x22x+n
Since (x+1) is a factor of f(x),
then f(1)=0
m+1+2+n=0
mn=3........(1)
Since (x1) is a factor of f(x),
then f(1)=0
m+12+n=0
m+n=1.........(2)
Solving from (1) and (2) we get m=2 and n=1

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