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Question

If (x+1) and (x-1) are factors of mx³ +x² - 2x +n find the value of m and n

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Solution

Let, f(x)= mx3+x22x+n

Since (x+1) is a factor of f(x),

then f(−1)=0

⇒ −m+1+2+n=0

⇒ m−n=3........(1)

Since (x−1) is a factor of f(x),

then f(1)=0

⇒ m+1−2+n=0

⇒ m+n=1.........(2)

Solving from (1) and (2) we get m=2 and n=(−1)


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