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If x=1 and ...

Question

If $x = 1$ and $y = - 1$ , then find the value of $x^{2} - y^{2}$ .

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Solution

$x^{2} - y^{2} = (1)^{2} - (- 1)^{2} = 1 - 1 = 0$

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Similar questions

Q. find the value of x if y=1 when

y = (x + \sqrt{x^{2} - y^{2}}

x = 1; y = 2

find the values:

x^{2} + y^{2}

x^{2} + y^{2} = 25

x y = 12

, then the value of

x^{- 1} + y^{- 1}

x, y, z

satisfies the equations

x + log (x + \sqrt{x^{2} + 1}) = y

y + log (y + \sqrt{y^{2} + 1}) = z

z + log (z + \sqrt{z^{2} + 1}) = x

, then find the value of

{(1 - x)}^{2} + {(1 - y)}^{2} + {(1 - z)}^{2}

\frac{1}{x + 1} + \frac{2}{y + z} + \frac{2006}{2006} = 1

, find the value of

\frac{x^{2}}{x^{2} + x} + \frac{y^{2}}{y^{2} + y} + \frac{z^{2}}{z^{2} + 2006 z}

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