If -x-1 and y-x-x2-2-x3-3-x4-4- - - then x-

The correct option is D y=x x^2+x^3/3 x^4/4+.... y=log_e(1+x)⇒ 1+x=e^y ⇒ x=y+y^2/2!+y^3/3!+..... ...

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Logarithmic Inequalities

If |x|<1 and ...

Question

If |x| < 1 and $y = x - \frac{x^{2}}{2} + \frac{x^{3}}{3} - \frac{x^{4}}{4} + . . . . . . . . t h e n x =$

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Solution

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Similar questions

y = x - \frac{x^{2}}{2} + \frac{x^{3}}{3} - \frac{x^{4}}{4} + . . . \infty

| x | < 1

x = y + \frac{y^{2}}{a!} + \frac{y^{3}}{b!} + \dots \dots + \infty

a^{2} + b

y = 1 + x + \frac{x^{2}}{2!} + \frac{x^{3}}{3!} + \frac{x^{4}}{4!} + . . . . . . . \infty

\frac{d y}{d x} = y

x^{3} - x - 4

x^{4} - x^{3} - x^{2} + x + 3

x^{4} + x^{2} - 1

1

0

y = 1 - x + \frac{x^{2}}{2!} - \frac{x^{3}}{3!} + \frac{x^{4}}{4!} . . .

\frac{d^{2} y}{d x^{2}}

y = 1 + \frac{x}{1!} + \frac{x^{2}}{2!} + \frac{x^{3}}{3!} + \frac{x^{4}}{4!} + . . . . \infty

\frac{d y}{d x}

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