If $x_{1}$ be the size of the magnified image and $x_{2}$ the size of the diminished image in Lens Displacement Method, then the size of the object is

\sqrt{x_{1} x_{2}}

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x_{1} x_{2}

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x_{1}^{2} x_{2}

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x_{1} x_{2}^{2}

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Solution

The correct option is A $\sqrt{x_{1} x_{2}}$
The size of the object in accordance with the Fresnel's displacement law is given by $\sqrt{x_{1} x_{2}}$ .

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If x1 be the size of the magnified image and x2 the size of the diminished image in Lens Displacement Method, then the size of the object is

The correct option is A √x1x2The size of the object in accordance with the Fresnel's displacement law is given by √x1x2.

If $x_{1}$ be the size of the magnified image and $x_{2}$ the size of the diminished image in Lens Displacement Method, then the size of the object is

The correct option is A $\sqrt{x_{1} x_{2}}$
The size of the object in accordance with the Fresnel's displacement law is given by $\sqrt{x_{1} x_{2}}$ .