If $x^{- 1} h = 1$ , what does $h$ equal in terms of $x$ ?

- x

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\frac{1}{x}

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\frac{1}{x^{2}}

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x

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x^{2}

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Solution

The correct option is E $x$
We have, $x^{- 1} h = 1$
$\Rightarrow x \cdot x^{- 1} h = x$ , multiply both sides by $x$
$\Rightarrow x^{1 - 1} h = x$ , since $a^{m} \cdot a^{n} = a^{m + n}$
$\Rightarrow x^{0} h = h = x$ , since $a^{0} = 1$ if $a \neq 0$
Hence correct choice is option 'C'

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