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Question

If (x−1) is a factor of ax3−bx2+cx, what is the value of a3−b3+c3?


A

2abc

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B

-2abc

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C

3abc

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D

-3abc

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Solution

The correct option is D

-3abc


p(x)=ax3bx2+cx

If (x - 1) is a factor then x = 1 is the zero of polynomial


p(1) = 0

p(1)=ab+c=0

It can be written as a+(b)+c=0

We know that if a+b+c=0, then a3+b3+c3=3abc

So, a3+(b)3+c3=3a(b)c=3abc


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