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Question

Question 22
If x + 1 is a factor of ax3+x22x+4a9, then find the value of a.

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Solution

Let p(x)=ax3+x22x+4a9
Since, x + 1 is a factor of p(x), p(-1) = 0 [Using Remainder Theorem].
a(1)3+(1)22(1)+4a9=0
a+1+2+4a9=0
3a6=0 3a=6
a=63=2
Hence, the value of a is 2.

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