Question

If $(x-1)$ is a factor of $m{x}^2-\sqrt{2}x+1=0$, then the value of 'm ' is

• A. $\sqrt{2}$
• B. $\sqrt{2}+1$
• C. $1$
• D. $\sqrt{2}-1$

Answer 1

The correct option is D $\sqrt{2}-1$

$(x-1)$ is a factor of $m{x}^2-\sqrt{2}x+1=0,$ then $x=1$ is zero of a given polynomial
Put x=1 in the given equation, we get
m$(1{)}^2-\sqrt{2}(1)+1=0$
$m-\sqrt{2}+1=0$
$\Rightarrow m=\sqrt{2}-1$