Question

If (x − 1) is a factor of polynomial f(x) but not of g(x) , then it must be a factor of

(a) f(x) g(x)

(b) −f(x) + g(x)

(c) f(x) − g(x)

(d) $\left\{f\left(x\right)+g\left(x\right)\right\}g\left(x\right)$

Answer 1

Asis a factor of polynomial f(x) but not of g(x)

Therefore

Now,

Let

Now

Therefore (x − 1) is also a factor of f(x).g(x).

Hence, the correct option is (a).