If (x+1)is a factor of x2−3ax+3a−7, then the value of a is
A
1
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B
-1
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C
0
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D
-2
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Solution
The correct option is A 1 Since x+1 is a factor of the polynomial p(x)=x2−3ax+3a−7 Therefore, by Factor theorem p(−1)=0 ⇒(−1)2−3a(−1)+3a−7=0 ⇒1+3a+3a−7=0⇒a=1 Option A is correct.