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Question

If x = 1 is a root of equation
x4+ax3+bx2+cx1=0 repeated thrice, then (a + b + 2c) is equal to

A
0
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B
1
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C
-1
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D
2
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Solution

The correct option is C 2
Product of roots =1
Fourth root =1
x4+ax3+bx2+cx1=(x1)3(x+1)
(x313x(x1))(x+1)
(x33x2+3x1)(x+1)
x43x3+3x2x +x33x2+3x1
x42x3+2x 1=0
a=2
b=0
c=2
a+b+2c=2+0+4=2

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