If (x + 1) is factor of the polynomial (2x² + kx) then the value of k is
(a) –2
(b) –3
(c) 2
(d) 3

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Solution

(c) 2

$(x + 1) is a factor of 2 x^{2} + k x . So, - 1 is a zero of 2 x^{2} + k x . Thus, we have : 2 \times {(- 1)}^{2} + k \times (- 1) = 0 \Rightarrow 2 - k = 0 \Rightarrow k = 2$

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