If x=1 is the equation of the common radical axis and (2,3) is one limiting point of a coaxial system, then the other limiting point is
A
(3,0)
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B
(0,3)
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C
(0,1)
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D
(0,−3)
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Solution
The correct option is B(0,3) x=1 is the equation of the common radical axis
So, all centre of the circle lie on the line perpendicular to x=1 and passing through (2,3) So, the line in which all centres lie is y=3 and P is the mid-point of limiting points. [r1=r2] So, other limiting point is x=2×1−2=0 and y=2×3−3=3 (0,3) is the other limiting point.