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Question

If (x - 1) is the factor of f(x) = x2−ax+2, find the value of a.

A
-2
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B
-3
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C
3
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D
1
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Solution

The correct option is C 3
Given: f(x) = x2ax+2, x - 1 is the factor of f(x).

Factor theorem: If x - a is the factor of f(x), then f(a) = 0.

(x - 1) is the factor of f(x) = x2ax+2, so f(1) = 0.

f(1) = 12a(1)+2
0 = 3 - a
a = 3

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