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Question

If x1/p=y1/q=z1/r and xyz=1, then the value of p+q+r=?

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Solution

x1/p=y1/q=z1/r=k (say)
x=kp,y=kq,z=kr
xyz=1 (given)
kp.kq.kr=1
k(p+q+r)=1.
(p+q+r)=0.

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