If x<1, sum the series 1+2x+3x2+4x3+.... upto infinity.
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Solution
Given that x<1 Let S=1+2x+3x2+4x3.........∞ Multiplying both sides by x, we get Sx=0+x+2x2+3x3........∞ Subtract both eqns, we get S(1−x)=1+x+x2+x3........∞ Clearly, this is an infinite series with common ratio x<1 ⇒S(1−x)=11−x ⇒S=1(1−x)2