CameraIcon
CameraIcon
SearchIcon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

If |x|<1,then the coefficient of xn in the expansion of (1+x+x2+x3+....)2 is

A
n
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
n1
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
n+2
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
n+1
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
Open in App
Solution

The correct option is D n+1
As 1+x+x2+x3+=(1x)1
(1+x+x2+.....)2=(1x)2
=1+2x+3x2+......
Therefore, coefficient of xn is n+1.

flag
Suggest Corrections
thumbs-up
18
Join BYJU'S Learning Program
Join BYJU'S Learning Program
CrossIcon