If x = 1, then the value of
2+x1+√3+x+2−x2−√2−x=?
2
6
3
1
None of these
2+x1+√3+x+2−x2−√2−x=2
If x=1√3+1 then the value of x+1x is
If x is positive, the sum of infinity of the series 11+x−1−x(1+x)2+(1−x)2(1+x)2−(1−x)3(1+x)4+.... is
If x=3+2√2,thenthevalueof(√x+1√x) is:
If f(x)=⎧⎪⎨⎪⎩x3,x<03x−2,0≤x≤2x2+1,x>2 Then find the value(s) of x for which f(x)=2.