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Rolle's Theorem

If √x+1 + √x-...

Question

If √x+1 + √x-1 = 2 , then the value of x is

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x = \frac{1}{2 - \frac{1}{2 - \frac{1}{2 - x}}}, (x \neq 2)

, then the value of x is ________?

If x*2+1/x*2=27,then value of x+1/x is

Q. If x^2+1/x^2=7, then value of x+1/x is

x^{2} + x + 1 = 0

, then the value of

(x + 1 / x)^{2} + (x^{2} + 1 / x^{2})^{2} + . . . . . + (x^{27} + 1 / x^{27})^{2}

x = \frac{1}{2},

then the value of

x + \frac{1}{1 + \frac{1}{1 + \frac{1}{x}}}

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Rolle's Theorem

Standard XII Mathematics

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