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Question

If x1, x2 are the roots of ax2 + bx + c = 0 and x1+d, x2+d are the roots of px2 + qx + r = 0, d 0 then


A

b24ac=q24pr

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B

ap+d=bq+d=cd+r

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C

d=bpaq2ap

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D

a + = p

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Solution

The correct option is C

d=bpaq2ap


ax2 + bx + c = 0 has roots x1, x2
x1+x2=ba, x1x2=ca|x1x2|=(x1+x2)24x1x2=b2a24ca=b24ac|a| ...(1)
px2 + qx + r = 0 has roots x1+d1 x2+d
(x1+d)+(x2+d)=qp, (x1+d)(x2+d)=rp
|x1x2|=1|p|q24pr ...(2)
From (1) & (2)
b24aca2=q24prp2Now 2d=qp(x1+x2)2d=aq+bpap d=aq+bp2ap


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