If x-1 - x-6- find x2-1 - x2 and x4-

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Cube Root Using Prime Factorisation

If x+1 / x=6,...

Question

If x + (1/x) = 6, find x² + (1/x²) and x⁴ +

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Solution

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(x - \frac{1}{x}) = 6,

(x^{2} + \frac{1}{x^{2}})

(x^{4} + \frac{1}{x^{4}})

x + \frac{1}{x} = \sqrt{5}

x^{2} + \frac{1}{x^{2}}

x^{4} + \frac{1}{x^{4}}

x + \frac{1}{x} = 5

x^{2} + \frac{1}{x^{2}}

x^{4} + \frac{1}{x^{4}}

If $x + \frac{1}{x} = \sqrt{5}$ , find the values of $x^{2} + \frac{1}{x^{2}} a n d x^{4} + \frac{1}{x^{4}}$ .

x + \frac{1}{x} = - 2

(x^{2} + \frac{1}{x^{2}}) \times

(x^{4} + \frac{1}{x^{4}})

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