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Question

If (x1,y1) and (x2,y2) are the extremities of a focal chord of the parabola 3y2=4x, then x1x2+y1y2 is equal to pq where p,q are co-prime. Then value of qp is

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Solution

If (at21,2at1),(at22,2at2) are the ends of a focal chord of a parabola y2=4ax, then t1t2=1
Here, x1=at21=13t21, x2=13t22
y1=23t1, y2=23t2
x1x2+y1y2
=19(t1t2)2+49t1t2=1949=13=pqqp=2

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