If $(x + 1, y - 2) = (3, 1)$ , find the values of $x$

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Solution

Given $(x + 1, y - 2) = (3, 1)$
$\Rightarrow x + 1 = 3 ∴ x = 2$
$y - 2 = 1 ∴ y = 3$

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