If x-1- y-2 and z-3- find the value of x2-y2-2 x y z

Given: x =1 y = 2 z = 3 Substituting x = 1, y = 2 and z = 3 in the given equation (x2 + y2 + 2xyz): 12 #160;+ #160;22 #160; #160;+ #160;2123 #8658 ...

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Byju's Answer

Standard VII

Mathematics

Solution of a Simple Linear Equation

If x=1, y=2 a...

Question

If x = 1, y = 2 and z = 3, find the value of x² + y² + 2xyz.

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Solution

Given:
x =1
y = 2
z = 3

Substituting x = 1, y = 2 and z = 3 in the given equation (x² + y² + 2xyz):

${(1)}^{2} + {(2)}^{2} + 2 (1) (2) (3) \Rightarrow 1 + 4 + 12 = 17 \frac{}{}$

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If x = 1, y = 2 and z = 3, find the value of x2 + y2 + 2xyz.

Given: x =1 y = 2 z = 3 Substituting x = 1, y = 2 and z = 3 in the given equation (x2 + y2 + 2xyz): 12 + 22 + 2123⇒1 + 4 + 12 = 17

If x = 1, y = 2 and z = 3, find the value of x² + y² + 2xyz.

Given:
x =1
y = 2
z = 3

Substituting x = 1, y = 2 and z = 3 in the given equation (x² + y² + 2xyz):

${(1)}^{2} + {(2)}^{2} + 2 (1) (2) (3) \Rightarrow 1 + 4 + 12 = 17 \frac{}{}$